Given: Circle K(O), , M2220a=(X+45)\Xb0,, Ke =(X+20)\Xb0, Ew=(3x)\Xb0 , Find: Kw
Given: circle k(O),
m∠A=(x+45)°,
KE =(x+20)°
EW=(3x)°
Find: KW
Answer:
KW=160
Step-by-step explanation:
m∠A=1/2(KW)
Sub: x+45=1/2(x+20+3x)
x=35
KW=x+20+3x
KW=35+20+3(35)
KW=160
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